Randy's Rules for Finding Virgin Websurfer Passwords
This method will result in a list of Password possibilities. These guidelines are preferable to having no heuristics at all, but hopefully someone will soon unlock the formula that will yield the one working Password for each Key. Until that formula is found, here are the guidelines for identifying a list of possible Passwords for each Key:
First, note whether the Key is greater than or less than 2500. If the Key is less than 2500, use method "A" below. If the Key is 2500 or greater, use method "B" below.
Method A (for Keys less than 2500):
1) Note whether the Key is less than "1000". If so, consider "0" (zero) to be the first digit of the Key, converting it to a four-digit Key. If the Key is equal to 1000 or more, then no such alteration is needed since it is already four digits. (As an example, if the Key is "334", then consider the Key as "0334". As another example, if the Key is "989", then consider the Key as "0989".)
2) Next, add 10,000 to the Key number, making it a five digit Key. (Example, if the Key is "0334", then the new Key is "10334". Another example, if the Key is "2112", then the new Key is "12112".)
3) Note the first three digits of the Key, and subtract 24 from that. This yields possibility #1 for the first two digits of the Password. Second, subtract 25 from the first three digits of the Key, which yields possibility #2 for the first two digits of the Password. (Example, if the Key is "10334", then possibility #1 for the first two Password digits is "79" since 103 minus 24 equals 79. Possibility #2 for the first two Password digits is "78" since 103 minus 25 equals 78. In this example, all 26 passwords will begin with either "78xx" or "79xx".)
4) Now consider the last two digits of the Key. Those two digits are possibility #1 of the last two digits of the Password. Next, to find the remaining possibilities, add and subtract the following list of numbers to the last two digits of the Key: 1, 2, 3, 4, 27, 28, 29, 30, 31, 95, 96, and 97. Note that anything yielding a number less than zero ("00") or greater than 99 ("99") can be discarded. (So, for example, if the last two digits of the Key are "50", then the list of possibilities for the last two digits of the Password are: 50, 49, 51, 48, 52, 47, 53, 46, 54, 23, 77, 22, 78, 21, 79, 20, 80, 19, and 81. Remember that you don't add or subtract 95, 96, or 97 to "50" in this example because that would result in possibilities less than zero or greater than 99.)
Method B (for Keys equal to or greater than 2500):
1) Note the first two digits of the Key, and subtract 24 from that. This yields possibility #1 for the first two digits of the Password. Second, subtract 25 from the first two digits of the Key, which yields possibility #2 for the first two digits of the Password. (Example, if the Key is "3914", then possibility #1 for the first two Password digits is "15" since 39 minus 24 equals 15. Possibility #2 for the first two Password digits is "14" since 39 minus 25 equals 14. In this example, all 26 passwords will begin with either "14xx" or "15xx".)
2) Now consider the last two digits of the Key. Those two digits are possibility #1 of the last two digits of the Password. Next, to find the remaining possibilities, add and subtract the following list of numbers to the last two digits of the Key: 1, 2, 3, 4, 27, 28, 29, 30, 31, 95, 96, and 97. Note that anything yielding a number less than zero ("00") or greater than 99 ("99") can be discarded. (So, for example, if the last two digits of the Key are "50", then the list of possibilities for the last two digits of the Password are: 50, 49, 51, 48, 52, 47, 53, 46, 54, 23, 77, 22, 78, 21, 79, 20, 80, 19, and 81. Remember that you don't add or subtract 95, 96, or 97 to "50" in this example because that would result in possibilities less than zero or greater than 99.)
That's it. I feel confident regarding these guidelines, but of course anything is fallible, so keep us all posted.
Randy
